Solve a one-step equation
Solve x − 9 = 14.
Add 9 to both sides: x − 9 + 9 = 14 + 9, so x = 23.
Check: 23 − 9 = 14. ✓
Forming and solving linear equations in one and two variables using the balance method — the KJSEA workhorse.
📖 3 min read · 5 worked examples · 7 practice questions
A linear equation is an equation in which the variable (usually x or y) is raised only to the power of one — never squared, cubed or under a root sign. Examples: x + 5 = 12, 3y − 7 = 8, 2x + 3y = 12. The word linear comes from the fact that, when graphed, every linear equation produces a straight line.
Linear equations are everywhere in real life: working out how many minutes of M-Pesa airtime you can afford, calculating distances with rate × time, sharing a bill between friends. The CBC Mathematics syllabus from Grade 7 onwards spends a lot of time on this skill because it is the foundation for every other algebraic technique that follows.
Standard form of a linear equation:
The balance method (one variable):
Treat the equation as a balance scale. Whatever you do to one side, you MUST do to the other to keep it balanced. The aim is to isolate the variable on one side.
Step-by-step rules:
Solving simultaneous equations (two variables):
When you have two equations in two unknowns, you need both to find unique values for x and y. Three common methods:
Word problems — three-step pattern:
Common mistakes to avoid:
CBC Grade 4–5 introduces the use of letters in number sentences; Grade 6 covers simple linear equations with one variable; Grade 7 covers linear equations and linear inequalities in one variable, balance method, and word problems; Grade 8 introduces simultaneous equations in two variables; Grade 9 extends to graphical solutions and the equation of a straight line — material that appears in KJSEA and senior school Mathematics.
Solve x − 9 = 14.
Add 9 to both sides: x − 9 + 9 = 14 + 9, so x = 23.
Check: 23 − 9 = 14. ✓
Solve 3x + 7 = 22.
Step 1 — subtract 7 from both sides: 3x = 15. Step 2 — divide both sides by 3: x = 5.
Check: 3(5) + 7 = 15 + 7 = 22. ✓
Solve 2(x + 3) = 14.
Step 1 — expand the bracket: 2x + 6 = 14. Step 2 — subtract 6 from both sides: 2x = 8. Step 3 — divide by 2: x = 4.
Three friends shared a meal of KES 1,200 equally. One of them, Ali, also paid an extra KES 150 for soda. How much did Ali pay altogether?
Let each person's share = x. Then 3x = 1,200, so x = 400. Ali paid *400 + 150 = KES 550.
Solve: x + y = 10 and x − y = 4.
Add the two equations: 2x = 14, so x = 7. Substitute into x + y = 10: 7 + y = 10, so y = 3.
Answer: x = 7, y = 3.
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