Grade 8Mathematics

Common Solids

Cubes, cuboids, prisms, cylinders, cones, pyramids; nets, surface area, volume.

📖 5 min read · 3 worked examples · 4 practice questions

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The lesson

Today we're beginning our Grade 8 geometry unit on common solids—cubes, cuboids, prisms, cylinders, cones, and pyramids. By the end of this lesson you'll know how to recognize their nets, and you'll be able to calculate surface area and volume. First, let's look at the list of solids on the slide. These shapes appear in everyday Kenyan life: the wooden crate that holds mangoes is a cuboid, a water tank is a cylinder, and the roof of a traditional hut often forms a pyramid. Notice how each solid can be unfolded into a flat pattern, called a net. We'll explore those nets shortly, because they help us see how many faces each shape has and how to compute surface area. Before we move on, does anyone have a question about what a net looks like or where you might have seen one in real life?

Everyone, let's start by asking: what exactly is a solid? A solid is a three‑dimensional shape that has length, width, and height. Here you can see the key ideas written out: a solid has length, width, and height. Think of a brick—that's a perfect cube. A wooden box is a cuboid, and the water tank we use on farms is a cylinder. At this pie chart. It shows the percentages of each solid type used in Kenyan construction: cubes like bricks make up about 40%, cuboids such as wooden crates about 35%, and cylinders like water tanks roughly 25%. Why does this matter? Understanding the shapes we build with helps us calculate material needs, plan budgets, and design safer structures. To recap, a solid has three dimensions, common examples are bricks, wooden boxes, and water tanks, and the chart shows how frequently each appears in our local construction projects.

Class, let's explore the shapes we use every day – cubes and cuboids. These solid figures are everywhere, from a dice on the board to the water tank at the market. First, a cube has six equal square faces. Imagine a perfectly stacked set of sugar cubes – each side looks the same. A cuboid, on the other hand, has rectangular faces that can be different lengths, like a typical brick or a rectangular storage box. For surface area: for a cube it's 6 a², where a is the edge length. For a cuboid we add the areas of all three pairs of faces: 2(lw + lh + wh). Think of wrapping a gift – you need to cover every side. Volume: a cube holds a³ cubic units, while a cuboid holds l · w · h. That's the amount of space inside – like how much water fits in a rectangular tank. Take a look at this comparison table. It lines up the formulas side by side, making it easy to remember which one to use for each shape. Any questions before we move on? Remember, recognizing these formulas will help you solve real‑world problems, from calculating how much sand fills a storage crate to designing a cube‑shaped playground block.

Everyone, let's explore right prisms – solid shapes whose bases are identical and stack straight up along the height. First point: the base shape repeats along the height. Notice the bullet that says the base repeats – that's why we call it a "right" prism. At this 3‑D sketch. You can see the same shape at the bottom and top, connected by vertical edges. Surface area. The formula is 2 × BaseArea plus Perimeter × Height. The first term accounts for the two bases, the second for the side faces. For volume, simply multiply BaseArea by Height. Imagine a grain storage silo in Kenya – a rectangular prism. Its capacity is the area of the floor times the height of the silo. Finally, here's the net of a right prism. When you cut the prism open and lay it flat, you get the base shape plus a rectangle for each side – useful for visualising surface area.

Let's talk about cylinders – a solid with a circular base and a vertical height. First, remember the base is a circle and the height runs straight up, just like a typical water tank. The surface area formula is 2π r (r + h). This adds the area of the two circles and the curved side. The volume formula is π r² h, which tells us how much space is inside the cylinder. For example, imagine a water tank at a rural school with a radius of 2 meters and a height of 5 meters. Using the volume formula, we get π × 2² × 5 ≈ 62.8 cubic metres of water. Any questions before we move on to applying these formulas to real‑world problems?

Everyone, let's wrap up what we've learned about three‑dimensional solids. First, remember the formulas for each shape—volume and surface area—so you can solve real‑world problems like the capacity of a water tank or the material needed for a market stall roof. Second, using nets helps you visualise how a flat pattern folds into a solid, making surface‑area calculations much easier. Finally, practice with local examples—like measuring the volume of a grain silo or the surface area of a rectangular prism-shaped crate—will strengthen your intuition. Keep reviewing these formulas and try creating your own nets at home. See you next class.

Worked examples

– Cube

Let's work through Example 1, a cube that could represent a storage box in our classroom. First, we are given the edge length of the cube: 0.5 metres. To find the surface area, we use the formula 6 × (edge)². Substituting 0.5 m gives 6 × (0.5)² = 1.5 square metres. Next, the volume is (edge)³. (0.5)³ = 0.125 cubic metres, the amount of space the box can hold. We have the surface area at 1.5 m² and the volume at 0.125 m³, which tells us how much material we need and how much we can store.

– Cylinder

Class, let's work through Example 2, where we need to find the volume of a cylindrical water tank for the clinic. Here is the picture of the tank – a simple cylinder. Remember, a cylinder's volume is calculated with the formula π r² h. The problem tells us the radius is 1 metre and the height is 2 metres. Plugging those numbers in, we get π × 1² × 2, which is about 6.28 cubic metres. This tank can hold roughly six and a quarter cubic metres of water – enough to supply the clinic for several days during the dry season. To recap: radius = 1 m, height = 2 m, volume ≈ 6.28 m³. Any questions before we move on?

– Pyramid

Class, let's work through Example 3, which asks us to find the surface area of a triangular roof on a school building. First, note the given data: the base triangle has an area of 12 m², the slant height is 3 m, and the perimeter of the base is 12 m. We use the surface‑area formula = base area + ½ × perimeter × slant height. Plugging in the numbers gives 12 + ½ × 12 × 3 = 30 m², so the roof's total surface area is 30 square meters.

Practice questions

  • First, the rectangular water tank. Remember the formula for the volume of a cuboid: length × width × height.
  • The cylindrical market‑stall tank. For total surface area we add the areas of the two circular ends (2 × πr²) and the curved side (2 πr h).
  • For the triangular prism roof. The net consists of two identical triangular bases and three rectangular side faces that unfold into a long strip.
  • Finally, the square‑based pyramid storage shed. The volume formula is (1/3) × base‑area × height.

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